"""

Broken bytecode objects can easily crash the interpreter.



This is not going to be fixed.  It is generally agreed that there is no

point in writing a bytecode verifier and putting it in CPython just for

this.  Moreover, a verifier is bound to accept only a subset of all safe

bytecodes, so it could lead to unnecessary breakage.



For security purposes, "restricted" interpreters are not going to let

the user build or load random bytecodes anyway.  Otherwise, this is a

"won't fix" case.



"""



import types



co = types.CodeType(0, 0, 0, 0, '\x04\x71\x00\x00', (),

                    (), (), '', '', 1, '')

exec co

